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题目链接
- f(1) = 1
- f(2) = 1 + 1 = 2
- f(3) = 1 + 2 + 1 = 4
- f(4) = 1 + 2 + 4 + 1 = 8
所以 f(n) = 2 n − 1 ^{n-1} n−1
import java.util.Scanner;public class Solution {public int jumpFloorII(int target) {return 1 << (target - 1);}
}
题目链接
所以 f(n) = 2 n − 1 ^{n-1} n−1
import java.util.Scanner;public class Solution {public int jumpFloorII(int target) {return 1 << (target - 1);}
}